(3x^2+x-1)(4x+5)=0

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Solution for (3x^2+x-1)(4x+5)=0 equation: 


Simplifying
(3x2 + x + -1)(4x + 5) = 0

Reorder the terms:
(-1 + x + 3x2)(4x + 5) = 0

Reorder the terms:
(-1 + x + 3x2)(5 + 4x) = 0

Multiply (-1 + x + 3x2) * (5 + 4x)
(-1(5 + 4x) + x(5 + 4x) + 3x2 * (5 + 4x)) = 0
((5 * -1 + 4x * -1) + x(5 + 4x) + 3x2 * (5 + 4x)) = 0
((-5 + -4x) + x(5 + 4x) + 3x2 * (5 + 4x)) = 0
(-5 + -4x + (5 * x + 4x * x) + 3x2 * (5 + 4x)) = 0
(-5 + -4x + (5x + 4x2) + 3x2 * (5 + 4x)) = 0
(-5 + -4x + 5x + 4x2 + (5 * 3x2 + 4x * 3x2)) = 0
(-5 + -4x + 5x + 4x2 + (15x2 + 12x3)) = 0

Combine like terms: -4x + 5x = 1x
(-5 + 1x + 4x2 + 15x2 + 12x3) = 0

Combine like terms: 4x2 + 15x2 = 19x2
(-5 + 1x + 19x2 + 12x3) = 0

Solving
-5 + 1x + 19x2 + 12x3 = 0

Solving for variable 'x'.

The solution to this equation could not be determined.

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